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Re: [xsl] cannot assign val to sort key
Subject: Re: [xsl] cannot assign val to sort key From: Joerg Pietschmann <joerg.pietschmann@xxxxxx> Date: Sat, 09 Feb 2002 16:53:41 +0100 |
alex <shortestpath@xxxxxxxxx> wrote: > From an asp page I pass values for sort key and sort > order. [...] But I can't seem to assign assign the values > of these variables to my <xsl:sort>. Here's what I'm > doing: > > <xsl:sort select="$sortKey" order="{$sortOrder}" /> You expect the processor to evaluate the sort key expression twice, which doesn't happen. The processor evaluates $sortKey and gets whatever you assigned the variable, it wont evaluate this again just because it looks like the selection expression you want it to have used. To work around this, if you have only simple element names there, you can use select="*[name()=$sortKey]". This is a FAQ BTW, check the archives. You probably also want to check the documentation of your processor whether and how an evaluate() function is supported. Your sort order should work fine, you just didn't notice because with your code all elements get the same sort key and therefore always stay in document order. HTH J.Pietschmann XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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Re: [xsl] cannot assign val to sort, Thomas B. Passin | Thread | [xsl] Proper xsl coding for ?, Brad Cox |
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