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Subject: [xsl] xslt and JSP 1.2 From: Kevin.Gutch@xxxxxxxxxxx Date: Thu, 10 Jan 2002 15:03:32 -0500 |
Hello everyone, I am trying to output JSP 1.2 from a stylesheet. I am stumbling on one issue. I am sure it is user error but can not figure out what is going on. My transformation works fine if I just output html code. However, if I try to output JSP 1.2 the resulting page wants to add the xml document that the transform was done on to the top of the output page.See below. Any suggestion? RESULT: <?xml version="1.0" encoding="UTF-8"?> <jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version ="1.2"><jsp:text><html><head><title>Stylesheet parameter</title></head><body><h2>XML source</h2><p>Hello</p><h2>Stylesheet parameter</h2><p>The param1 stylesheet parameter has been set to default value.</p></body></html></jsp:text></jsp:root> STYLESHEET: <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version ="1.0"> <xsl:param name="param1" select="'default value'"/> <xsl:template match="/"> <jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="1.2"> <jsp:text> <html> <head><title>Stylesheet parameter</title></head> <body> <h2>XML source</h2> <p><xsl:value-of select="."/></p> <h2>Stylesheet parameter</h2> <p>The param1 stylesheet parameter has been set to <xsl:value-of select="$param1"/>.</p> </body> </html> </jsp:text> </jsp:root> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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