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And I want to show this information sorted in a HTML table. I perform this with the code:
<xsl:template match="/ALMACEN">
<xsl:for-each select="ARTICULO">
<xsl:sort select="NOMBRE_FAMILIA"/>
<xsl:sort select="NOMBRE_SUBFAMILIA"/>
<xsl:sort select="DESCRIPCION_CORTA"/>
...
</xsl:for-each>
</xsl:template>
My problem is that I have to compare each 'ARTICULO' with the following 'ARTICULO', but once they are sorted.
For this, I think the best solution is to store in a variable all the nodes 'ARTICULO', sort them, and compare each of them with the following.
I hope you have enought information with it, otherwise I´ll be pleased to give it to you.
Thanks friend!
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Re: [xsl] Sorting a variable that contains a nodeset
Subject: Re: [xsl] Sorting a variable that contains a nodeset From: "rafael vazquez" <rc_vazquez@xxxxxxxxxxx> Date: Thu, 10 Jan 2002 17:58:08 +0100 |
From: "cutlass" <cutlass@xxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: Re: [xsl] Sorting a variable that contains a nodeset Date: Thu, 10 Jan 2002 16:11:35 -0000
Hello Rafeal,
----- Original Message ----- From: "rafael vazquez" <rc_vazquez@xxxxxxxxxxx> > Hi All! > I have a variable containing a nodeset as > <xsl:variable name="var" select="//ARTICULO"/> > and I want to order this nodeset by the node 'NOMBRE_FAMILIA'. How can I > perform it? Exists any function that sorts the variable?
depends on how you generate the variable, and if u want to use an extension function to continue manipulating it ( node-set() function that is).
but since u didnt give me a snippet of xml that is representative, i cant really give u an explicit example...
we would like to help,
cheers, jim fuller
My XML file is: <ALMACEN> <ARTICULO> <DESCRIPCION_CORTA>chuletas cerdo</DESCRIPCION_CORTA> <DESCRIPCION_LARGA>chuletas cerdo extra</DESCRIPCION_LARGA> <NOMBRE_FAMILIA>alimentacion</NOMBRE_FAMILIA> <NOMBRE_SUBFAMILIA>carnes</NOMBRE_SUBFAMILIA> </ARTICULO> <ARTICULO> <DESCRIPCION_CORTA>chuletas marrano</DESCRIPCION_CORTA> <DESCRIPCION_LARGA>chuletas marrano extra</DESCRIPCION_LARGA> <NOMBRE_FAMILIA>alimentacion</NOMBRE_FAMILIA> <NOMBRE_SUBFAMILIA>verduras</NOMBRE_SUBFAMILIA> </ARTICULO> <ALMACEN>
And I want to show this information sorted in a HTML table. I perform this with the code:
<xsl:template match="/ALMACEN">
<xsl:for-each select="ARTICULO">
<xsl:sort select="NOMBRE_FAMILIA"/>
<xsl:sort select="NOMBRE_SUBFAMILIA"/>
<xsl:sort select="DESCRIPCION_CORTA"/>
...
</xsl:for-each>
</xsl:template>
My problem is that I have to compare each 'ARTICULO' with the following 'ARTICULO', but once they are sorted.
For this, I think the best solution is to store in a variable all the nodes 'ARTICULO', sort them, and compare each of them with the following.
The variable is formed as: <xsl:variable name="nodos" select="//ARTICULO"/>
I hope you have enought information with it, otherwise I´ll be pleased to give it to you.
Thanks friend!
_________________________________________________________________
MSN Photos es la manera más sencilla de compartir e imprimir sus fotos: http://photos.latam.msn.com/Support/WorldWide.aspx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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