Re: [xsl] stupid newbie question

Try this:
XML:
<document>
<title>title</title>
<drawing output="filename.jpg"/>
<p>paragraph</p>
</document>

XSLT:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:template match="/">
      <xsl:apply-templates />
   </xsl:template>

   <!-- default behaviour:
   <xsl:template match="*">
                <xsl:apply-templates/>
   </xsl:template>

        and with templates al you do is change that def. behaviour,
        so when you only specify a template for that certain element, all
        other will be processed according to the above template..

        more or less anyway...
        :-)
   -->

hey all -

i'm new to the list and XSL so this might seem like a silly question
(and maybe one that's already been asked a dozen times)...

i need to apply a stylesheet that goes in and changes only one tag in
my document.  specifically

<drawing output="filename.jpg">

needs to become

<img src="filename.jpg">

like in html.  my stylesheet has one single template that does this,
but when i apply it, ALL of the other tags in the document disappear.
i assume that without a template for a specific tag, my transformer is
mapping the other tags to nothing at all.  is there a simple way
around this?  or do i need to make templates for each and every tag
that transforms them into the result document as what they were in the
source?

thanks in advance for all your help.  and apologies if i'm wasting
everyone's time.

-greg

----------

the poems to come are for you and for me and are not for most people.


XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Ronald Heller
Technisch Consultant

Coltbaan 27b
3439 NG Nieuwegein
Telefoon 030 60 56 675
Telefax  030 60 56 324
Website www.salience.nl
ronald@xxxxxxxxxxx
Mobiel   06 20 41 25 77
ICQ 135511393