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Subject: [xsl] Saxon custom extensions problem From: "Gustaf Liljegren" <gustaf.liljegren@xxxxxx> Date: Tue, 16 Oct 2001 12:13:47 +0200 |
Finally upgraded to Saxon 6.4.3. :-) Now I have some questions on the documentation for custom extensions to Saxon, namely the extensibility.html document: 'With the short-cut technique, the URI for the namespace identifies the class where the external function will be found. The namespace URI must either be "java:" followed by the fully-qualified class name (for example xmlns:date="java:java.util.Date"), [...] The class must be on the classpath.' Okay, here's my custom Java extension function: class ReverseString { public static String reverseIt(String source) { int i, len = source.length(); StringBuffer dest = new StringBuffer(len); for (i = (len - 1); i >= 0; i--) { dest.append(source.charAt(i)); } return dest.toString(); } } I can take Java syntax, but I'm not so familiar with terminology like "fully-qualified class name". I have no class library, just a single function, and in the same directory as the stylesheet. So if I want to use it as an extension for an FO transformation, I guess I should write: <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:my="java:ReverseString"> And later on, I use it like this: <xsl:value-of select="my:reverseIt(.)"/> Something is clearly wrong, and it seems to happen at the namespace declaration already: The URI java:ReverseString does not identify an external Java class Transformation failed: run-time errors were reported For the future, it would be helpful to include two tiny (but complete) examples in the documentation: one for importing, and another for exporting content from the stylesheet to a Java application. Gustaf Liljegren XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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