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Re: [xsl] catching the last node still satisfying a condition
Subject: Re: [xsl] catching the last node still satisfying a condition|
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 13 Sep 2001 16:00:26 +0100
> If we agree the final result is an ordered (meaning indexed access, as in an
> array) set (meaning no duplicate) of nodes. Right ?
No. The result of an XPath select is always unordered (hence set). All
these sets are subsets of an ordered set of nodes, but individual
selections do not have an order. So for example
2 selects the second ancestor in reverse order but
<xsl:variable name="a" select="ancestor::*"/>
$a is just the unoordered set of nodes: it doesn'r "remember" that it
was collected in any particular order.
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Michael Kay - Thu, 13 Sep 2001 15:12:26 +0100