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RE: [xsl] catching the last node still satisfying a condition

Subject: RE: [xsl] catching the last node still satisfying a condition
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Thu, 13 Sep 2001 14:56:35 +0100

> You can't without for-each cycle. because [] operands return
> 1 recordset not
> an array.

eh???

A filter expression using [] returns neither a recordset nor an array, it
returns a node-set.

Mike Kay
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
Re: [xsl] catching the last node still satisfying a condition, (continued) Dimitar Peikov - Thu, 13 Sep 2001 15:25:23 +0300 Guillaume Rousse - Thu, 13 Sep 2001 14:47:38 +0200 Dimitar Peikov - Thu, 13 Sep 2001 16:11:27 +0300 Guillaume Rousse - Thu, 13 Sep 2001 15:31:25 +0200 Michael Kay - Thu, 13 Sep 2001 14:56:35 +0100 <= Dimitar Peikov - Thu, 13 Sep 2001 17:10:38 +0300 Guillaume Rousse - Thu, 13 Sep 2001 16:30:51 +0200 David Carlisle - Thu, 13 Sep 2001 16:00:26 +0100 Michael Kay - Thu, 13 Sep 2001 15:34:31 +0100

Current Thread

Re: [xsl] catching the last node still satisfying a condition, (continued)
- Dimitar Peikov - Thu, 13 Sep 2001 15:25:23 +0300
  - Guillaume Rousse - Thu, 13 Sep 2001 14:47:38 +0200
    - Dimitar Peikov - Thu, 13 Sep 2001 16:11:27 +0300
    - Guillaume Rousse - Thu, 13 Sep 2001 15:31:25 +0200
  - Michael Kay - Thu, 13 Sep 2001 14:56:35 +0100 <=
    - Dimitar Peikov - Thu, 13 Sep 2001 17:10:38 +0300
    - Guillaume Rousse - Thu, 13 Sep 2001 16:30:51 +0200
    - David Carlisle - Thu, 13 Sep 2001 16:00:26 +0100
    - Michael Kay - Thu, 13 Sep 2001 15:34:31 +0100

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Re: [xsl] catching the last node st, Guillaume Rousse	Thread	Re: [xsl] catching the last node st, Dimitar Peikov
[xsl] Xpath newbie question, Eric Smith	Date	RE: [xsl] Re: XSL-List Digest V3 #1, Michael Kay
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RE: [xsl] catching the last node still satisfying a condition

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