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Re: [xsl] XPath help


Subject: Re: [xsl] XPath help
From: "Jeffrey Langdon" <jl_xsl@xxxxxxxxxxx>
Date: Fri, 07 Sep 2001 17:29:01 +0000

Jeni:

I can always count on Mike Kay and yourself.

You two, as well as some other longtime subscribers answer the questions very thoroughly. Your extra effort is appreciated.

Regards,

Jeffrey Langdon


From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: "Jeffrey Langdon" <jl_xsl@xxxxxxxxxxx>
CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] XPath help
Date: Fri, 7 Sep 2001 16:53:38 +0100

Hi Jeffrey,

> Any ideas on which answer is correct?

It depends how much you care about namespaces.

*[not(name()='a' or name()='b')]

Gives you all the elements aside from a and b elements that are in the
default namespace in their document. I'd tend to steer clear of this
because the default namespace could be anything at all.

[not(self::a or self::b)]

Gives you all the elements aside from a and b elements that are in no
namespace. Use this if the a and b elements that you want to ignore
don't have a namespace or if you're not using namespaces at all.

*[not(local-name()='a' or local-name()='b')]

Gives you all the elements aside from a and b elements in any
namespace. Use this if you want to ignore all a and b elements no
matter what namespace they're in.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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