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Re: [xsl] document() path created from xml
Subject: Re: [xsl] document() path created from xml From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Tue, 4 Sep 2001 11:34:59 +0100 |
Hi Jeroen, > I'm trying to load an xml document with document(), every file has > an id and I need to take this id from the originaly loaded xml, I > tried this with a variable but I can't get it to work, this one of > the xsls I tried: > > <xsl:variable name="path"> > document('../data/institutions/institutions_country0.xml')/institutions > </xsl:variable> > > <xsl:apply-templates select="$path"/> When you set a variable using its content, then you create a result tree fragment; in this case, you create a result tree fragment with a single text node whose value is "document('../data/institutions/institutions_country0.xml')/institutions". Instead, you want to evaluate the XPath, to make the $path variable hold the resulting institutions element (I think). To do that, use the select attribute on xsl:variable, rather than its content, to set the variable: <xsl:variable name="path" select="document('../data/institutions/institutions_country0.xml') /institutions" /> > A related question; is there any way of seeing what the result of an > expression is? I know I'm doing something wrong but "Reference to > variable or parameter 'path' must evaluate to a node list" is a bit > vague, I would like to see what's actually happening... I find it helpful to send debugging messages with xsl:message and use xsl:copy-of to show the value of variables. For example: <xsl:message> $path: <xsl:copy-of select="$path" /> </xsl:message> Where you see the messages depends on the way you're using the processor. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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