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Re: [xsl] simple question with
Roman,
This sounds like a job for the stepwise identity transform -- check out the XSLT spec, section 7.5. (Or it must be in the XSL FAQ: look for 'identity'.)
Oh, heck:
That will copy all the nodes on at a time; you can add templates to override it for the specialized processing you need.
At 10:31 AM 7/17/01, you wrote:
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Re: [xsl] simple question with
Subject: Re: [xsl] simple question with <xsl:copy-of> From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Tue, 17 Jul 2001 11:43:07 -0400 |
Roman,
This sounds like a job for the stepwise identity transform -- check out the XSLT spec, section 7.5. (Or it must be in the XSL FAQ: look for 'identity'.)
Oh, heck:
<xsl:template match="node()|@*> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template>
That will copy all the nodes on at a time; you can add templates to override it for the specialized processing you need.
Cheers, Wendell
At 10:31 AM 7/17/01, you wrote:
Hi alltogther!
I've just a simple questtion: How can I copy all the tags from the body of my XML-source document into my XSL-stylesheet in order of their occurance and additionally adapt some of these tags with additional templates? I thought that I could make it with a simple <xsl:copy-of>, but the I just get all the text nodes....
<xsl:template match="body">
<form method="post"> <xsl:attribute name="action"> <xsl:value-of select="$all"/> </xsl:attribute> <xsl:copy-of select="."/> <xsl:apply-templates/> </form> </xsl:template>
<xsl:template match="foo"> .....
</xsl:template>
Could you please help me?
Yours, Roman
> Roman Huditsch (RH ) > _____________________________________________________________________ > hico Informations- und Kommunikations-Management Gesellschaft m.b.H. > TechLab, Thomas A. Edison Straße 2. > A-7000 Eisenstadt / Austria > phone: +43/2682/704-61-00; fax: +43/2682/704-71-61-10 > e-mail:support@xxxxxxxx; r.huditsch@xxxxxxxx > >
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