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RE: [xsl] How can I do the xsl file
Subject: RE: [xsl] How can I do the xsl file From: Rene de Vries <RdVries@xxxxxxxxxxx> Date: Thu, 12 Jul 2001 10:43:19 +0200 |
And as usual several solutions for one problem: <xsl:template match="ITEM"> <xsl:if test="AT/@ID='22'"> <xsl:copy> <xsl:copy-of select="AT[@ID='22']"/> </xsl:copy> </xsl:if> </xsl:template> Greetings Rene { @ @ } ^ \__/ "You don't need eyes to see, you need vision!" -----Oorspronkelijk bericht----- Van: laurence_zhang [SMTP:laurence_zhang@xxxxxxxx] Verzonden: donderdag 12 juli 2001 10:05 Aan: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Onderwerp: [xsl] How can I do the xsl file Hi, I want to do convert from : <ITEM ID="12" CAPTION="first"> <AT ID="11" SET="5"/> <AT ID="22" SET="5"/> <VALUE>1</VALUE> </ITEM> <ITEM ID="13" CAPTION="sec"> <AT ID="22" SET="5"/> </ITEM> <ITEM ID="14" CAPTION="thr"> <VALUE>0</VALUE> </ITEM> to: <ITEM ID="12" CAPTION="first"> <AT ID="22" SET="5"/> <VALUE>1</VALUE> </ITEM> <ITEM ID="13" CAPTION="sec"> <AT ID="22" SET="5"/> </ITEM> that means: 1.remove element ATTR which ID=11; 2.remove item that have no ATTR ID=22. How can I do the xsl file ? Thanks a lot. ______________________________________ =================================================================== ?AAEAa.N?c?OOEIa (http://mail.sina.com.cn) ??OAEO>u?I?AI.Io?AIA??IiIi???a?iE?E?EO>u?? (http://dailynews.sina.com.cn/c/272235.html) ??OAEO>u?I?A?????AIAA?Ii?A?A?iEO>u?o???? (http://dailynews.sina.com.cn/c/266499.html) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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