RE: [xsl] How to sort a nodeset referenced by a variable?

Subject: RE: [xsl] How to sort a nodeset referenced by a variable?
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Wed, 4 Jul 2001 09:45:51 +0100

> I am doing something like this
>
> <xsl:variable name="filterdNode" select="//*" />
>
> <xsl:variable name="sortedList">
> <xsl:for-each select="$filterNode/someElement">
>  <xsl:sort select="$fileterNode/secondElement">

The value of your sort key will be the same for every node in the
collection. It's meaningless to use a sort key whose value doesn't depend on
the context node.

Mike Kay
Software AG


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Current Thread

[xsl] How to sort a nodeset referenced by a variable?
- Kumar . Shailendra - Tue, 3 Jul 2001 16:13:24 -0400 (EDT)
  - David Carlisle - Tue, 3 Jul 2001 18:11:47 -0400 (EDT)
  - Michael Kay - Wed, 4 Jul 2001 04:47:22 -0400 (EDT) <=
    - Kumar . Shailendra - Thu, 5 Jul 2001 11:00:14 -0400 (EDT)
    - Kumar . Shailendra - Thu, 5 Jul 2001 11:24:38 -0400 (EDT)
      - Wendell Piez - Thu, 5 Jul 2001 12:06:07 -0400 (EDT)
      - Michael Kay - Thu, 5 Jul 2001 12:42:19 -0400 (EDT)

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RE: [xsl] How to sort a nodeset referenced by a variable?