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Re: [xsl] Problem with simple xsl:when test expression

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First, I hope that this is only a typing error:
    </annotation>


This is illegal.  You probably mean "<annotation/>".  But that would kill
you right there (but you'd get an error message)

Second, it looks like a namespace issue.  You have

<xsl:template match="xsd:simpleType">

but your XML sample doesn't use the "xsd" prefix.  So either it's declared
earlier or it's not declared at all.  If it's not declared, the
xsd:simpleType won't match because of the prefix, and if it is, the other
matches won't work because they would need to be prefixed too.

Cheers,

Tom P

[Phil Mitchell]

> I am trying to write a test expression for a when clause that will be true
> when the context node has a child 'restriction' element whose 'base'
> attribute is "string" -- i.e. <restriction base="string">. I think this
> clause should simply be:
>
>          <xsl:choose>
>   <xsl:when test="./restriction[@base='string']">
>   </xsl:when>
>          </xsl:choose>
>
> But it doesn't seem to work -- it doesn't match. What is wrong with this?
> Here is the context node:
>
> <simpleType name="MedlarsNameString">
>    </annotation>
>    <restriction base="string">
>    </restriction>
> </simpleType>
>
> And here is the stylesheet fragment (slightly edited -- yes, the second
> choose block is meant to be nested in an otherwise block.):
>
> <xsl:template match="xsd:simpleType">
>    <xsl:param name="elementName"/>
>     <xsl:choose>
>        <xsl:when test="@name='TextBlock'">
>         Do this....
>        </xsl:when>
>        <xsl:otherwise>
>          <xsl:choose>
>   <xsl:when test="./restriction[@base='string']">
>   Print here.
>             </xsl:when>
>          </xsl:choose>
>        </xsl:otherwise>
>      </xsl:choose>
> </xsl:template>
>



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