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RE: [xsl] count all the following nodes of a perticular parent

Subject: RE: [xsl] count all the following nodes of a perticular parent
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Thu, 28 Jun 2001 12:38:45 +0100
Or

count(following-sibling::node()/descendent-or-self::node() |
      following-sibling::node/descendent-or-self::node()/@*)

(depending on what you want).

Cheers,
Wendell

At 01:22 PM 6/28/01, Mike wrote: 
> i want to count all the following nodes from the current node
> of the same
> parent
> can anybody give me a way to do this?

count(following-sibling::node())

Mike Kay
Software AG



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