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RE: [xsl] count all the following nodes of a perticular parent

Subject: RE: [xsl] count all the following nodes of a perticular parent
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Thu, 28 Jun 2001 13:22:35 +0100

> i want to count all the following nodes from the current node 
> of the same
> parent
> can anybody give me a way to do this?

count(following-sibling::node())

Mike Kay
Software AG

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Current Thread
[xsl] count all the following nodes of a perticular parent Jayaranga Subasinghe - Thu, 28 Jun 2001 15:51:30 +0600 Jarno Elovirta - Thu, 28 Jun 2001 13:12:59 +0300 Michael Kay - Thu, 28 Jun 2001 13:22:35 +0100 <= Wendell Piez - Thu, 28 Jun 2001 12:38:45 +0100 <Possible follow-ups> Ben Robb - Thu, 28 Jun 2001 11:04:33 +0100 Jayaranga Subasinghe - Fri, 29 Jun 2001 10:06:09 +0600 Jarno Elovirta - Fri, 29 Jun 2001 07:26:15 +0300

Current Thread

[xsl] count all the following nodes of a perticular parent
- Jayaranga Subasinghe - Thu, 28 Jun 2001 15:51:30 +0600
  - Jarno Elovirta - Thu, 28 Jun 2001 13:12:59 +0300
  - Michael Kay - Thu, 28 Jun 2001 13:22:35 +0100 <=
    - Wendell Piez - Thu, 28 Jun 2001 12:38:45 +0100
  - <Possible follow-ups>
  - Ben Robb - Thu, 28 Jun 2001 11:04:33 +0100
  - Jayaranga Subasinghe - Fri, 29 Jun 2001 10:06:09 +0600
    - Jarno Elovirta - Fri, 29 Jun 2001 07:26:15 +0300

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RE: [xsl] count all the following n, Jarno Elovirta	Thread	RE: [xsl] count all the following n, Wendell Piez
RE: [xsl] Non-hierarchy XML -> hier, Benoit_Aumars	Date	FW: [xsl] (How to display O/P of an, Sripriya S
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RE: [xsl] count all the following nodes of a perticular parent

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