RE: [xsl] count all the following nodes of a perticular parent

Subject: RE: [xsl] count all the following nodes of a perticular parent
From: "Jarno Elovirta" <jarno@xxxxxxxxxxxxxx>
Date: Thu, 28 Jun 2001 13:12:59 +0300

> i want to count all the following nodes from the current node of the same
> parent

count(following-sibling::node())

Sini

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Current Thread
[xsl] count all the following nodes of a perticular parent Jayaranga Subasinghe - Thu, 28 Jun 2001 15:51:30 +0600 Jarno Elovirta - Thu, 28 Jun 2001 13:12:59 +0300 <= Michael Kay - Thu, 28 Jun 2001 13:22:35 +0100 Wendell Piez - Thu, 28 Jun 2001 12:38:45 +0100 <Possible follow-ups> Ben Robb - Thu, 28 Jun 2001 11:04:33 +0100 Jayaranga Subasinghe - Fri, 29 Jun 2001 10:06:09 +0600

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RE: [xsl] count all the following nodes of a perticular parent