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Subject: [xsl] add <br/> From: "John Wang" <jwang@xxxxxxxxxxx> Date: Tue, 22 May 2001 14:49:00 -0500 |
Hi, I am writing xsl to transform a xml to html. I have a table, the number of rows varies. After the table, I have a button. What I want is put the button more less in the same position no matter how many rows will be. here is my xml: <?xml version="1.0"?> <records> <record> <branch>001</branch> <cycle>001</cycle> <status>Started, Stock tags/sheets have been printed.......</status> <date>01/04/00</date> </record> <record> <branch>001</branch> <cycle>002</cycle> <status>Fronzen, 000 of 001 batch(s) entered...............</status> <date>04/21/99</date> </record> <record> <branch>001</branch> <cycle>004</cycle> <status>Started, Stock tags/sheets have been printed.......</status> <date>04/21/99</date> </record> </records> Here is the html <form action="....."> <table> <tr> <td>001</td><td>001</td>... </tr> <tr> <td>001</td><td>001</td>... </tr> <tr> <td>001</td><td>001</td>... </tr> </table> <br/> <br/> <input type="submit" value="Go"/> ... </form> the question is how can I write a xsl to determine how many <br/> will be output to the html. For example, if there are 3 record, I will output 2 <br/>, if there are 1 record, I want to output 4 <br/>. I am not sure I make my question clear. But you can figure it out. Thanks a lot. -John XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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