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RE: [xsl] Node comparison
Subject: RE: [xsl] Node comparison From: "Don Stinchfield" <destinchfield@xxxxxxxx> Date: Sun, 15 Apr 2001 11:02:59 -0400 |
Kevin, As a first attempt I used the <xsl:element> tag to solve the problem. I queried for the correct value by comparing element names. This is based on the assumption that for tag names you meant "<Value 1>" to be "<Value_1>" and not "<Value qualifier="1">. <xsl:template match="Parent_2"> <xsl:copy> <xsl:for-each select="*"> <xsl:variable name="destName" select="name()"/> <xsl:element name="{$destName}"> <xsl:value-of select="/test1/Parent_1/*[name()=$destName]/text()"/> </xsl:element> </xsl:for-each> </xsl:copy> </xsl:template> Hope this is what you were looking for. Regards, Don > Kevin_Gutch@xxxxxxxxxxx > Sent: Saturday, April 14, 2001 7:12 PM > > Having two different XML's joined on an entity reference I need to > compare values underneath two different parent nodes without having to use > a $Position Variable. The reason being is that I may not have a one to one > relationship. So > with an example below I would like to use my XSLT to base the values of > Parent 2 on the like values in Parent 1. > > <?xml version="1.0" encoding="UTF-8"?> > <Parent 1> > <Value 1>1</Value 1> > <Value 2>0</Value 2> > <Value 3>1</Value 3> > <Value 4>0</Value 4> > </Parent 1> > <Parent 2> > <Value 1> </Value 1> > <Value 2> </Value 2> > <Value 2> </Value 2> > <Value 3> </Value 3> > <Value 4> </Value 4> > </Parent 2> > > I would like the following results: > > <Parent 1> > <Value 1>1</Value 1> > <Value 2>0</Value 2> > <Value 3>1</Value 3> > <Value 4>0</Value 4> > </Parent 1> > <Parent 2> > <Value 1>1</Value 1> > <Value 2> 0</Value 2> > <Value 2> 0</Value 2> > <Value 3> 1</Value 3> > <Value 4> 0</Value 4> > </Parent 2> > > Any ideas on how to do this? > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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