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RE: [xsl] Copy XHTML element contents without base tag

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> Now, as far as I can see there are two ways of processing 
> this in XSLT:
> 
> <xsl:template match="xfragment">
> 	<xsl:copy-of select="." />
> </xsl:template>
> 
> Unfortunately this ends up including the <xfragment> tags in 
> the output,
> which I can't really have.
> 
> The other way I can see is 
> 
> <xsl:template match="xfragment">
> 	<xsl:copy-of select="./*" />
> </xsl:template>
> 
> Unfortunately this removes any text elements which are direct 
> children of
> the xfragment tags (e.g. the phrase 'This is a fragment of 
> XHTML' in the
> above example).
> 
> Does anyone know any better ways of making this copy?
> 
<xsl:template match="xfragment">
 	<xsl:copy-of select="node()" />
</xsl:template> 

Mike Kay
Software AG

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