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[xsl] looking for the / char
Subject: [xsl] looking for the / char From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx (by way of Mulberry Technologies List Owner) Date: Sat, 3 Feb 2001 22:58:03 -0500 |
From: "Mirick, John" <jmirick@xxxxxxxxxxxx> To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: looking for the / char Date: Fri, 2 Feb 2001 14:52:48 -0500 MIME-Version: 1.0 X-Mailer: Internet Mail Service (5.5.2653.19) Content-Type: text/plain; charset="iso-8859-1"
Eck! Im a bit baffled right now... Im trying to get a template that will just remove spaces and / from a given string. The code is based on some I found in the FAQ. It replaces the spaces fine.... however it wont replace the /.... Im not sure why. If anyone has a spare moment Im sure it is blatantly obvious to some of you. But Im at the point where Im ready to pull my hair out. I have also tried both the decimal and hex codes (/ and /) rather than just using the slash with no luck. -john
<xsl:template name="replaceCharsInString"> <xsl:param name="stringIn"/> <xsl:choose> <xsl:when test="contains($stringIn,' ')"> <xsl:value-of select="concat(substring-before($stringIn,' '),'%20')"/> <xsl:call-template name="replaceCharsInString"> <xsl:with-param name="stringIn" select="substring-after($stringIn,' ')"/> </xsl:call-template> </xsl:when> <xsl:when test="contains($stringIn,'/')"> <xsl:message>2</xsl:message> <xsl:value-of select="concat(substring-before($stringIn,'/'),'%2f')"/> <xsl:call-template name="replaceCharsInString"> <xsl:with-param name="stringIn" select="substring-after($stringIn,'/')"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$stringIn"/> </xsl:otherwise> </xsl:choose> </xsl:template>
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