RE: [xsl] Can sets have order?

>There is no query which yields visibly different results.

????? 

There are ***many*** Xpath expressions, which will produce different
results when you swap the two nodes:

1. generate-id($node)

2. count($node/preceding::node())

3. count($nodeset[position() < 4 and count(preceding::*) = $num1])

The above is constructed assuming that node1 and node2 are respectively
$nodeset[3] 
and
$nodeset[5]

and that $num1 is equal to count(node1/preceding::*) 

The expression 
count($nodeset[position() < 4 and count(preceding::*) = $num1])

will evaluate to 1 given the original nodeset.

It will evaluate to 0 on the nodeset in which the deep-equal nodes
node1 and node2 were swapped.

Dimitre.


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