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RE: [xsl] Using XLS to transform/join two XML docs.
Subject: RE: [xsl] Using XLS to transform/join two XML docs. From: Kay Michael <Michael.Kay@xxxxxxx> Date: Wed, 20 Dec 2000 09:56:52 -0000 |
> Effectively, I'm trying to do a SQL join without the db. The general case of a join of two tables having a many-to-many relationship certainly isn't easy in XSLT (I leave it as a challenge for the reader!). But your example is one-to-many, and that's quite straightforward. > > So, I'd like to start with: > > <one> > <a b="1">First Choice</a> > <a b="2">Second Choice</a> > <a b="3">Third Choice</a> > </one> > > <two> > <x id="1" b="1" this="that" them="those" /> > <x id="2" b="3" this="that" them="those" /> > </two> > > And wind up with: > > <three> > <x id="1" b="First Choice" this="that" them="those" /> > <x id="2" b="Third Choice" this="that" them="those" /> > </three> > > <xsl:template match="two/x"> <xsl:copy> <xsl:copy-of select="@id | @this | @that"/> <xsl:attribute name="id"> <xsl:value-of select="//one/a[@b = current()/@b]"/> </xsl:attribute> </xsl:copy> </xsl:template> or, for efficiency with a large data set, use a key in the predicate. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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