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Re: [xsl] Using XLS to transform/join two XML docs.
Subject: Re: [xsl] Using XLS to transform/join two XML docs. From: Goetz Bock <bock@xxxxxxxxxxx> Date: Wed, 20 Dec 2000 00:03:30 +0100 |
> This may be a complete bonehead question, but I don't have enough experience > to know the difference :) > <one> > <a b="1">First Choice</a> > <a b="2">Second Choice</a> > <a b="3">Third Choice</a> > </one> > > <two> > <x id="1" b="1" this="that" them="those" /> > <x id="2" b="3" this="that" them="those" /> > </two> > > And wind up with: > > <three> > <x id="1" b="First Choice" this="that" them="those" /> > <x id="2" b="Third Choice" this="that" them="those" /> > </three> > > Is this possible, or is it beyond the scope of XSL? It's no problem (at last it's possible), but you must know the first document's location: <template match="two"> <tree> <apply-templates select="x"/> </tree> </template> <template match="x"> <element name="x"> <attribute name="id"><value-of select="@id"/></attribute> <attribute name="b"><value-of select="document('where ever')//one/a[b=@b]"/></attribute> <attribute name="them"><value-of select="@them"/></attribute> </element> </template> This might not be right, but it's close. Cu, Goetz.
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