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Subject: Calling any servlet within xml From: Mala Ramakrishnan <mala@xxxxxxxxxxxxx> Date: Thu, 2 Nov 2000 17:27:38 -0400 (EST) |
Hi,
I can't seem to figure out what could be wrong with my code, maybe I'm
just not doing this the right way, it's my first time. I used pieces of
information from the archives to do this.
I need to pass in parameters to an xml file - which are the servlet url,
and a couple of parameters for the servlet. The servlet returns an xml
file which has info to create a form. I get a blank screen on my browser
when I call the xml file. Here is how my code looks:
HandleForm.xml
---------------
<?xml version="1.0"?>
<?cocoon-process type="xsp"?>
<?xml-stylesheet href="HandleForm.xsl" type="text/xsl"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsp:page xmlns:xsp="http://www.apache.org/1999/XSP/Core"
xmlns:util="http://www.apache.org/1999/XSP/Util">
<page>
<xsl:element name="util:include-uri">
<xsl:attribute name="href">
<xsp:logic>
<![CDATA[
String[] url = request.getParameters("url");
String[] op = request.getParameters("operation");
String[] stage = request.getParameters("stage");
]]>
<xsl:value-of select=
"concat(url, '?operation=', op, '&stage=', stage)"
/>
</xsp:logic>
</xsl:attribute>
</xsl:element>
</page>
</xsp:page>
</xsl:stylesheet>
HandleForm.xsl
---------------
<?xml version="1.0"?>
<?cocoon-process type="xsp"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsp:page xmlns:xsp="http://www.apache.org/1999/XSP/Core"
xmlns:util="http://www.apache.org/1999/XSP/Util">
<xsl:template match="input">
<xsl:processing-instruction name="cocoon-format">
type="text/html"
</xsl:processing-instruction>
<html>
<head>
<title> New Router </title>
</head>
<body bgcolor="#ffffff">
Hiya! The formatting for the xml returned by the servlet goes
here.
</body>
</html>
</xsl:template>
</xsp:page>
</xsl:stylesheet>
~
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