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Re: Testing position of parent
Subject: Re: Testing position of parent From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 26 Oct 2000 18:13:44 GMT |
> I believe they will return the same result, but I'm > wondering if there's any tradeoffs to each approach. > > You said: test="parent::lg[not(preceding-sibling::*)]" > David C. said: test="not(parent::lg[preceding-sibling::*])" they are not actually equivalent, which was what I was alluding to when I said me> (exactly what you want depending on whether you also want to test me> whether the parent is lg. Mike's test is true if the parent node is an lg and it is the first element amongst its siblings. My test is true if it isn't the case that the parent is an lg and has preceding sibling elements. In particular if the parent isn't lg then my test will be true but Mike's will be false. But it may be that in the context you know its an lg anyway... David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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