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How To Access a param from style sheet
Subject: How To Access a param from style sheet From: Bharat.Chintapally@xxxxxxxxxxxxxxxxx Date: Wed, 18 Oct 2000 18:22:46 -0400 |
Hello: I am new to XSLT and also to this list. I have a quick question about accessing parameters from XSL style sheets. I am using Xalan XSLT processor in my servlet to transform XML into HTML using XSL. I am able to set the stylesheet param using xslProcessor.setStylesheetParam("sortBy", "receiverId"); Now I am trying to access this param in the xsl stylesheet to do my sorting.. I tried something like the following but I am not having much (/any) luck.. <xsl:sort select="*[name() = $sortBy]"/> Any help is really appreciated.. Thanks -- bharat --------------------------------------------------------------- Bharat Chintapally CommerceQuest Inc. bharat.chintapally@xxxxxxxxxxxxxxxxx New Phone # 813-639-6478 --------------------------------------------------------------- XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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