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Re: Accessing the XML declaration, the namespace-uri() function
Subject: Re: Accessing the XML declaration, the namespace-uri() function From: Miloslav Nic <nicmila@xxxxxxxx> Date: Fri, 05 Nov 1999 06:39:15 +0100 |
XT will do it automatically, if you use <xsl:output method='xml'/> (you can forbid this behavior) Look at http://zvon.vscht.cz/HTMLonly/XSLTutorial/Examples/Example85/exampleInOne.html Dylan Walsh wrote: > > Is it possible to somehow access the attributes of the <?xml > version="1.0"?> tag? I'm trying to create a stylesheet that will > generate a HTML view of any XML code, and I'd like it to begin with the > <?xml version="1.0"?> tag. So I was planning to write out something > like: > <?xml > then insert the attribute names & their values then close the tag: > ?> > > I've gotten this approach working for other processing instructions, but > is it possible with the XML declaration, and if so, how? Are they > attributes of the root node, or does "The XML declaration is not visible > to the XSL processor" mean it is truly impossible? > > Would it be safe to assume that the declaration is always <?xml > version="1.0"?> and hard code it, i.e.: > <?xml version="1.0"?> ? > > Also, does the namespace-uri() function work in XT? The XT webpage says > that namespace *axes* aren't supported, but what about the function? I > can't get it to produce anything (using <xsl:value-of > select="namespace-uri()> ). > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list -- *************************************************************** Dr. Miloslav Nic e-mail: nicmila@xxxxxxxx Department of Organic Chemistry TEL: +420 2 2435 5012 ICT Prague (VSCHT Praha) +420 2 2435 4118 FAX: +420 2 2435 4288 **************************************************************** Support free information exchange: http://zvon.vscht.cz **************************************************************** XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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