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RE: sorting & styling

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> 
> Sort, once, a list of elements and generate a table with the 
> sorted list, with the number of elements per row given in the stylesheet:
>
This falls into the general category of "grouping problems", they can be
done in XSLT but it isn't easy.

You need something like

<xsl:template name="do-the-rest">
  <xsl:param name="start"/>
  <xsl:param name="count"/>
  <tr>
  <xsl:for-each select="item[position()&gt;=$start and
position()&lt;$start+$count">
    <td>
    <xsl:value-of select="."/>
    </td>
  </xsl:for-each>
  </tr>
  <xsl:if test="$start + $count - 1 &lt; last()">
  <xsl:call-template name="do-the-rest">
    <xsl:with-param name="start" select="$start + $count"/>
    <xsl:with-param name="count" select="$count"/>
  </xsl:call-template>
  </xsl:if>  
</xsl:template>

<xsl:template match="data">
  <xsl:call-template name="do-the-rest">
    <xsl:with-param name="start" select="1"/>
    <xsl:with-param name="count" select="2"/>
  </xsl:call-template>
</xsl:template>

Mike Kay
  

 
> For example:
> 
> <data>
> <item>b</item>
> <item>a</item>
> <item>d</item>
> <item>c</item>
> </data>
> 
> gives, with 2 elements per row:
> 
> <table>
> <tr> <td>a</td> <td>b</td> </tr>
> <tr> <td>c</td> <td>d</td> </tr>
> </table>
> 
> 
> Olivier
> 
> 
> ---
> Olivier Corby, Acacia project, INRIA Sophia Antipolis
> email : Olivier.Corby@xxxxxxxxxxxxxxx tel : +33 4 92 38 78 71
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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