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Accessing current node attributes
Subject: Accessing current node attributes From: George Phillips <phillips@xxxxxxxxxxxx> Date: Mon, 14 Sep 1998 11:32:20 -0700 |
I'd like to write an XSL style sheet that reduces well-formed HTML down to a simple list of links. Something like this nearly sufficies: <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> <xsl:template match="a[attribute(href)]"> <A HREF="{.[attribute(href)]}"> <xsl:value-of expr="." /> </A> </xsl:template> </xsl:stylesheet> But "{.[attribute(href)]}" doesn't get me the HREF attribute of the current A node being processed. Not that I expect it to as it is not XSL-grammatically correct. In fact, I can't see any way to do this in XSL at all. Am I missing something or is this really not possible? -- George XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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